3-3y^2-1/2y-2=0

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Solution for 3-3y^2-1/2y-2=0 equation: 


y in (-oo:+oo)

3-(3*y^2)-((1/2)*y)-2 = 0

(-1/2)*y-3*y^2-2+3 = 0

1-3*y^2-1/2*y = 0

DELTA = (-1/2)^2-(-3*1*4)

DELTA = 49/4

DELTA > 0

y = ((49/4)^(1/2)+1/2)/(-3*2) or y = (1/2-(49/4)^(1/2))/(-3*2)

y = -2/3 or y = 1/2

y in { -2/3, 1/2 }

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